2009年5月16日星期六

傳教士與食人族

RIVER 3 個食人族跟 3個傳教士來到河邊。他們要渡河但岸邊得一隻只能載 2人的木筏。危險之處在於,若任何一邊岸上的食人族多於傳教士時,食人族便會將少數的傳教士吃掉。

問:怎樣才可將 6人安全送抵彼岸?

 

解答

5 則留言:

  1. 木筏要依以下方法往返五次半,就可將 6人安全送抵彼岸。
    b 代表木筏
    C 代表食人族
    M 代表傳教士

    3C3M b- 0C0M
    2C2M -b 1C1M
    2C3M b- 1C0M
    0C3M -b 3C0M
    1C3M b- 2C0M
    1C1M -b 2C2M
    2C2M b- 1C1M
    2C0M -b 1C3M
    3C0M b- 0C3M
    1C0M -b 2C3M
    2C0M b- 1C3M
    0C0M -b 3C3M

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  2. note that the solution can be symmetrical if the second last step is changed to '1C1M b- 2C2M'.
    ~siukin

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  3. symmetry is beautiful but boring;
    assymmetry is awkward but interesting-
    the dear world is shaped by these two forces...

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